If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2+x-0.16=0
a = 2; b = 1; c = -0.16;
Δ = b2-4ac
Δ = 12-4·2·(-0.16)
Δ = 2.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2.28}}{2*2}=\frac{-1-\sqrt{2.28}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2.28}}{2*2}=\frac{-1+\sqrt{2.28}}{4} $
| 19b-15b+3b-b=12 | | 2t-(-6)=10 | | 4x/5=-3.16 | | z/2+3=6 | | 7x–5+16+x=11x–x–3 | | 11x-10x=6 | | d/3-(-1)=3 | | 9+4x=-10x-4 | | 14r+6r=20 | | 1/11y-5=-8 | | 11y-5=-8 | | x+(1/3x)=80 | | 3=x+3-3=-6 | | 3/5=24=4-1/5f | | 1/4y+6=-7 | | 5x-7=3(2x-6) | | 5.7z-4.7z+8.1=-3.1 | | 58=6b | | 3x+45=8x-10 | | -10x-6=x+15 | | 0.4x+0.5(3)=2.3 | | x+4(5+x)=40 | | 3x^2+2x–16=0 | | x+4/2+x+5/5=6 | | 3v^2+2v–16=0 | | 9/15=x/30 | | 7x-(9x+5)=2x-25 | | 3v2+2v–16=0 | | (x^2-16)(x+5)/(x^2-25)(x^2+x-20)=0 | | x=2(-5.25) | | 20m^2-41m+2=0 | | 14x-30=96 |